1z0-830 Exam Dumps - Oracle Java SE Questions and Answers

In this code, three static methods from the Boolean class are used: logicalAnd, logicalOr, and logicalXor. Each method takes two boolean arguments and returns a boolean result based on the respective logical operation.

Evaluation of Each Statement:

Boolean.logicalAnd(1 == 1, 2 < 1)

Operands:

1 == 1 evaluates to true.

2 < 1 evaluates to false.

Operation:

Boolean.logicalAnd(true, false) performs a logical AND operation.

The result is false because both operands must be true for the AND operation to return true.

Output:

System.out.print(false); prints false.

Boolean.logicalOr(1 == 1, 2 < 1)

Operands:

1 == 1 evaluates to true.

2 < 1 evaluates to false.

Operation:

Boolean.logicalOr(true, false) performs a logical OR operation.

The result is true because at least one operand is true.

Output:

System.out.print(true); prints true.

Boolean.logicalXor(1 == 1, 2 < 1)

Operands:

1 == 1 evaluates to true.

2 < 1 evaluates to false.

Operation:

Boolean.logicalXor(true, false) performs a logical XOR (exclusive OR) operation.

The result is true because exactly one operand is true.

Output:

System.out.print(true); prints true.

Combined Output:

Combining the outputs from each statement, the final printed result is:

nginx

falsetruetrue

1. Valid Use Cases of var

var is alocal variable type inferencefeature.

The compilerinfers the type from the assigned value.

Example of valid use:

java

var a = 10; // Type inferred as int

var str = "Hello"; // Type inferred as String

2. Analyzing the Given Statements

Statement

Valid/Invalid

Reason

var a = 1;

Valid

Type inferred as int.

var b = 2, c = 3.0;

❌Invalid

var doesnot allow multiple declarationsin one statement.

var d[] = new int[4];

❌Invalid

Array brackets []are not allowedwith var.

var e;

❌Invalid

varrequires an initializer(cannot be declared without assignment).

var f = { 6 };

❌Invalid

{ 6 } is anarray initializer, which must have an explicit type.

var h = (g = 7);

Valid

g is assigned 7, and h gets its value.

Thus, the correct answers are:B, C, D, E

References:

Java SE 21 - Local Variable Type Inference (var)

Java SE 21 - var Restrictions

The jdeps tool is a Java class dependency analyzer that can be used to understand the static dependencies of applications and libraries. It provides several command-line options to customize its behavior.

Valid jdeps Options:

--generate-open-module: Generates a module declaration (module-info.java) with open directives for the given JAR files or classes.

--list-deps: Lists the immediate dependencies of the specified classes or JAR files.

--generate-module-info: Generates a module declaration (module-info.java) for the given JAR files or classes.

--print-module-deps: Prints the module dependencies of the specified modules or JAR files.

--list-reduced-deps: Lists the reduced dependencies, showing only the packages that are directly depended upon.

Invalid Option:

--check-deps: There is no --check-deps option in the jdeps tool.

Conclusion:

Option A (--check-deps) is not a valid option of the jdeps command.

The Java Platform Module System (JPMS), introduced in Java 9, modularizes the Java platform and applications. Understanding the behavior of named and unnamed modules is crucial.

B. The unnamed module exports all of its packages.

Correct. The unnamed module, which includes all code on the classpath, exports all of its packages. This means that any code can access the public types in these packages. However, the unnamed module cannot be explicitly required by named modules.

C. If a package is defined in both a named module and the unnamed module, then the package in the unnamed module is ignored.

Correct. In cases where a package is present in both a named module and the unnamed module, the version in the named module takes precedence. The package in the unnamed module is ignored to maintain module integrity and avoid conflicts.

F. If a request is made to load a type whose package is not defined in any known module, then the module system will attempt to load it from the classpath.

Correct. When the module system cannot find a requested type in any known module, it defaults to searching the classpath (i.e., the unnamed module) to locate the type.

Incorrect Options:

A. Code in an explicitly named module can access types in the unnamed module.

Incorrect. Named modules cannot access types in the unnamed module. The unnamed module can read from named modules, but the reverse is not allowed to ensure strong encapsulation.

D. We must add a module descriptor to make an application developed using a Java version prior to SE9 run on Java 11.

Incorrect. Adding a module descriptor (module-info.java) is not mandatory for applications developed before Java 9 to run on Java 11. Such applications can run in the unnamed module without modification.

E. The unnamed module can only access packages defined in the unnamed module.

Incorrect. The unnamed module can access all packages exported by all named modules, in addition to its own packages.

Why does the compilation fail?

TheJava switch statement does not support primitive type pattern matchingin switch expressions as of Java 21.

The case pattern case int i -> "integer"; isinvalidbecausepattern matching with primitive types (like int or long) is not yet supported in switch statements.

The error occurs at case int i -> "integer";, leading to acompilation failure.

Correcting the Code

Since myVar is of type Object,autoboxing converts 0 into an Integer.

To make the code compile, we should use Integer instead of int:

java

Object myVar = 0;

String print = switch (myVar) {

case Integer i -> "integer";

case Long l -> "long";

case String s -> "string";

default -> "";

};

System.out.println(print);

Output:

bash

integer

Thus, the correct answer is:Compilation fails.

References:

Java SE 21 - Pattern Matching for switch

Java SE 21 - switch Expressions