Authentic CompTIA Certification Exam DA0-001 Questions Answers

This is because the number of datapoints increases each day by approximately 20% of the total number from the day before. Therefore, to find the number of datapoints on the next day, we can use the formula:

Plugging in the given values, we get:

Since we are dealing with whole numbers, we can round up the result to the nearest integer, which is 10,600.

Comprehensive and Detailed In-Depth Explanation:

When incorporating new customer information from a survey into an existing customer contacts database, the appropriate data manipulation technique is:

Option B:Append

Rationale:Appending involves adding new records to the end of an existing dataset without altering the existing data. In this scenario, the analyst adds the new customer information as additional records in the database.

Option A:Join

Rationale:Joining combines data from two or more tables based on a related column, creating a new dataset with combined information. This is not necessary when simply adding new records.

Option C:Transform

Rationale:Transformation involves changing the format, structure, or values of data. While important in data processing, it doesn't pertain to adding new records.

Option D:Blend

Rationale:Data blending combines data from different sources into a single dataset, often used in analysis rather than updating a database with new records.

The correct answer is D. OUTER JOIN, seven rows.

An OUTER JOIN is a type of SQL join that returns all the rows from both tables, regardless of whether there is a match or not. If there is no match, the missing side will have null values.An OUTER JOIN can be either a LEFT JOIN, a RIGHT JOIN, or a FULL JOIN, depending on which table’s rows are preserved1

Using the example tables, a FULL OUTER JOIN query would look like this:

SELECT Cust_id, Order_id, Order_qty FROM Sales_table FULL OUTER JOIN Order_table ON Sales_table.Order_id = Order_table.Order_id;

The result of this query would be:

Cust_id | Order_id | Order_qty --------±---------±--------- 1 | 1 | 100 2 | 2 | 50 3 | 3 | 25 4 | 4 | 75 NULL | 5 | 10 NULL | 6 | 20 NULL | 7 | 15

As you can see, the query returns seven rows, one for each order in either table. The orders that are not in the Sales_table have null values for the Cust_id column.

To find the mean of the order quantity, we need to sum up the order quantities and divide by the number of rows. In this case, the mean is (100 + 50 + 25 + 75 + 10 + 20 + 15) / 7 = 42.14. Rounding to one decimal place, we get42.1as the mean of the order quantity.